50/2 × 5x =x = 4 ×××××××××××××××××××××××××××××××
1. 50/2 × 5x =x = 4 ×××××××××××××××××××××××××××××××
50/2 × 5x 50/2 × 5(4)25 × 20500
[tex]\boxed{ \colorbox{purple}{ \sf{ \color{violet}{༄Answer᭄By: ♡CHEMISTRY1♡ ࿐ }}}}[/tex]
Jawaban:50/2 × 5x = ?
x = 4
= 50/2 × 5(4)
= 25 × ( 5 × 4 )
= 25 × 20
= 500
Makasiii :32. 1. x² = -2x +152. x² = -5x + 50
Jawaban:
1.382(#82+2;+$+#
Penjelasan dengan langkah-langkah:
maaf ya kalo ada yang salah
3. Kuis [+50]: (x³+6x²-5x) dibagi (x-2) sama dengan
Cara ada difoto.
Hasil Bagi = x^2 + 8x + 11
Sisa Bagi = 22
#Soalkedelapanyggwjwbmkegambar
Jawaban:
Hasil bagi : x² + 8x + 11
Sisa bagi : 22
Jadi, (x³ + 6x² - 5x) dibagi (x - 2) = x² + 8x + 11 sisa 22
Penjelasan dengan langkah-langkah:
terlampir di gambar
4. Tentukan X pangkat 2 -5x -6 per x +1 yang jawab bakal gue kirimin pulsa 50 ribu sumpahhh.. ;)
[tex] \frac{x^2-5x-6}{x+1} = \frac{(x-6)(x+1)}{x+1} =x-6[/tex]x² - 5x - 6 / x+1
x² - 5x - 6
= (x-6)(x+1)
cara :
-6 = -6.1
-6+1 = -5
sesuai dengan varabel diatas, maka hasilnya demikian
(x-6)(x+1) / x+1
= x-6
5. Q. (+50)[tex] \sf \: 6x + 7 = \frac{5x - 7}{2} [/tex]x = .....
[tex]6x + 7 = \frac{5x - 7}{2} \\ [/tex]
[tex] \frac{6x + 7 = \dfrac{5x - 7}{2}}{} \times 2 \\ [/tex]
[tex]12x + 14 = 5x - 7[/tex]
[tex]12x - 5x = - 7 - 14[/tex]
[tex]7x = - 21[/tex]
[tex]x = \frac{ - 21}{7} \\ [/tex]
[tex]x = \frac{ - 3}{1} \\ [/tex]
[tex]x = \bold{ - 3}[/tex]
SOAL :
1) 6X + 7 = 5X - 7/2
= 12X + 14 = 5X - 7
= 12X + 14 - 5X = -7
= 12X + 5X = -7 - 14
= [ 12 - 5 ]X = -7 - 14
= 7X = -21
X = -21/7
X = -3
6. Kuis +50: Perhatikanlah pers. dibawah [tex]\displaystyle\sqrt[3]{\prod_{x=2}^4\left(\frac{x^2+2x}{x^2-1}\right)}=\:^n\log\left(\sum _{x=2}^5x^2+5x-6\right)[/tex] n = ....
Notasi Produk
Logaritma
Notasi Sigma
Penjabaran masing-masing ruas pd lampiran
ruas kiri = ruas kanan
2 = ⁿlog 100
100 = n²
n = √100
n = 10
n = 10
Pembahasan
[tex]\begin{aligned}&\underbrace{\sqrt[3]{\prod_{x=2}^4\left(\frac{x^2+2x}{x^2-1}\right)}}_{\begin{array}{c}a\end{array}}={}^n\log\underbrace{\left(\sum _{x=2}^5x^2+5x-6\right)}_{\begin{array}{c}b\end{array}}\\&\Large\text{$\Rightarrow {n}^a=b\quad....(i)$}\\&\qquad{\sf dengan\ }n > 0\,,\ n\ne1\end{aligned}[/tex]
Menentukan nilai a:
[tex]\begin{aligned}a&=\sqrt[3]{\prod_{x=2}^4\left(\frac{x^2+2x}{x^2-1}\right)}\\&=\sqrt[3]{\left(\frac{2^2+2(2)}{2^2-1}\right)\left(\frac{3^2+2(3)}{3^2-1}\right)\left(\frac{4^2+2(4)}{4^2-1}\right)}\\&=\sqrt[3]{\left(\frac{\cancel{8}}{3}\right)\left(\frac{\cancel{15}}{\cancel{8}}\right)\left(\frac{24}{\cancel{15}}\right)}\\&=\sqrt[3]{\frac{24}{3}}\ =\ \sqrt[3]{8}\\a&=\bf2\end{aligned}[/tex]
Menentukan nilai b:
[tex]\begin{aligned}b&=\sum_{x=2}^{5}\left(x^2+5x-6\right)\\&=\sum_{x=2}^{5}x^2\:+\:5\cdot\sum_{x=2}^{5}x\:-\:\sum_{x=2}^{5}6\\&=2^2+3^2+4^2+5^2\\&\quad\ +5(2+3+4+5)\\&\quad\ -(5-2+1)(6)\\&=4+9+16+25\\&\quad\ +5(14)\\&\quad\ -24\\&=54+70-24\\b&=\bf100\end{aligned}[/tex]
Menentukan nilai n dengan substitusi nilai a dan b ke pers. (i).
[tex]\begin{aligned}&\large\text{${n}^a=b$}\\&{\sf dengan\ }a=2\,,\ b=100\,,\ n > 0\,,\ n\ne1\\&\Rightarrow \large\text{${n}^2=100$}\\&\therefore\ \boxed{\ \large\text{$n=\bf10$}\ }\end{aligned}[/tex]
7. waktunya kuisss!5x × 2 = 50Nilai x?
Penjelasan dengan langkah-langkah:
5x × 2 = 50
10x = 50
x = 50/10
x = 5/1
x = 5
Jawab:
5x × 2 = 50
5x = 50 / 2
5x = 25
x = 25 / 5
x = 5
8. [tex] \frac{{x}^{2} - 5x - 4}{x + 3} > 1[/tex]pakai cara ya dapat 50 poin
x²-5x -4 / x +3 > 1
x² - 5x - 4> x + 3
x² - 6x -7 > 0
Ini jawabannya :) makasih :)9. Kuis +50: f(x) = 3x² + 5x, f'(2) = ......
[tex]f(x) = 3x² + 5x[/tex]
[tex]f'(2) = ({2 \times 3x})^{2 - 1} + {5x}^{1 - 1} [/tex]
[tex]f'(2) = {6x}^{1} + {5x}^{0} [/tex]
[tex]f'(2) = 6x + 5(1)[/tex]
[tex]f'(2) = 6(2) + 5[/tex]
[tex]f'(2) = 12 + 5[/tex]
[tex]f'(2) = 17[/tex]
[tex]{\colorbox{black}{\purple{\boxed{\colorbox{green}{\blue{ {࿐Answer ࿐ by : ❀BrainlyElite14❀:･ﾟ}}}}}}}[/tex]
Jawaban:
f(x) = 3x² + 5x
f'(x) = [tex]\sf\frac{d}{dx}[/tex](3x² + 5x)
f'(x) = 2×3x^(2-1) + 5x^(1-1)
f'(x) = 6x + 5
f'(2) = 6×2 + 5
f'(2) = 12 + 5
f'(2) = 17
10. Sederhanakan! (5^x+1)+(5^x+2)+(5x+3) ÷50 =310/4
Jawaban:
nihh 5 + 1 + 5 + 2 + 5 + 3 . 50 / 4 = 310
11. Nilai X dari 3(5x + 6)-2( x-4)=50
Jawaban:
3(5x+6)-2(x-4)=50
15x+18 - 2x+8=50
15x-2x+18+8=50
13x + 26=50
13x=50-26
13x=24
x=24 ÷ 13
x=1,8461538462
MAAF KALAU SALAH
12. Quiz (+50): 5x – 6 = 3x + 2 x³ = .......
Jawaban:
x³ = 64
Penjelasan dengan langkah-langkah:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
(5 - 3)x = 8
2x = 8
x = 8 / 2
x = 4
x³ = 4³
x³ = 4 × 4 × 4
x³ = 16 × 4
x³ = 64
» SPLSV______________________________
5x - 6 = 3x + 2
5x - 3x = 2 + 6
( 5 - 3 )x = 8
2x = 8
x = 8/2
x = 4
~~
nilai x³
= 4³
= 4 × 4 × 4
= 64[tex]~[/tex]
13. 1. 5x - 25 = 50 berapa nilai x2. 5x + 25 = 100 berapa nilai x
Soal :
1. 5x - 25 = 50 Berapa Nilai x ?
2. 5x + 25 = 100 Berapa Nilai x ?
Jawaban:1. x = 15
2. x = 15
Penjelasan dengan langkah-langkah:
1. 5x - 25 = 505x - 25 = 50
5x = 50 + 25
5x = 75
x = 75 : 5
x = 15
2. 5x + 25 = 1005x + 25 = 100
5x = 100 - 25
5x = 75
x = 75 : 5
x = 15
#SemogaMembantuJawab:
1. X = 5
2. X = 15
Penjelasan dengan langkah-langkah:
Lihat foto
14. tolong di bantu1. -150+ 250:(-5x(-25)=2. 750-(-2)x(-250)+(50)=3. 2 x (-75) + 250 -(300:(-6))=
Semoga membantu
Practice makes perfect
15. tentukan persamaan berikut x^2+5x=50
Jawaban:
X^2 + 5x - 50 = 0
(x-5) (x+10)
x1 = 5 x2 = - 10
16. 19. Pada gambar di bawah ini, tentukan nilai x, y, dan z. a. 25 *- 50 X-50 2 b. y 5x-80° 2x - 10 2
a. x - 50 + (x - 50) = 180
x - 50 + x - 50 = 180
2x - 100 = 180
2x = 180 + 100
2x = 280
x = 280/2
x = 140
y = x - 50
y = 140 - 50
y = 90
z = x - 50
z = 140 - 50
z = 90
b. 5x - 80 = 2x - 10
5x - 2x = -10 + 80
3x = 70
x = 70/3
x = 23,33
y + 5x - 80 = 180
y + 5(23,33) - 80 = 180
y + 116,65 - 80 = 180
y = 180 - 116,65 + 80
y = 143,35
z + 2x - 10 = 180
z + 2(23,33) - 10 = 180
z + 46,66 - 10 = 180
z = 180 - 46,66 + 10
z = 143,34
17. [+50]fungkomf(x) = 3x² + 5x + 3g(x) = 3x - 2( f o g )(3) = __
Penjelasan dengan langkah-langkah:
f(x) = 3x² + 5x + 3
g(x) = 3x - 2
( f o g )(3) = __
cari (fog)(x) terlebih dahulu(fog)(x) = f(g(x))
= 3(3x - 2)² + 5(3x - 2) + 3
= (9x - 6)² + 15x - 10 + 3
= 81x² - 108x + 36 + 15x - 10 + 3
= 81x² + (-108x + 15x) + (36 - 10 + 3)
= 81x² - 93x + 23
Nilai (fog)(3)(fog)(x) = 81x² - 93x + 23
(fog)(3) = 81(3²) - 93(3) + 23
= 81(9) - 279 + 23
= 729 - 279 + 23
= 450 + 23
= 473
18. Quiz (+50): Diketahui → f(x) = 2x+4 → g(x) = 5x² buktikanlah jika (((fog)⁻¹)'')⁻¹(√2) = (¹/₂₀∛25)+4
Jawab:
Komposisi, Invers, dan TurunanCatatan:
Jika [tex]\LaTeX[/tex] tidak muncul dengan semestinya, silahkan kunjungi dari web browser.
1. Tentukan invers f(x) dan g(x)
[tex]\large\text{$\begin{aligned}&f(x) = 2x+4\\&\implies f^{-1}(x)=\frac{x-4}{2}\\\\&g(x) = 5x^2\\&\implies g^{-1}(x)=\pm\sqrt{\frac{x}{5}}=\pm\frac{1}{\sqrt{5}}\sqrt{x}\\\end{aligned}$}[/tex]
2. Tentukan (fog)⁻¹
[tex]\large\text{$\begin{aligned}(f\circ g)^{-1}(x)&=\left (g^{-1}\circ f^{-1}\right)(x)\\&=\Biggl.\pm\frac{1}{\sqrt{5}}\sqrt{\frac{x-4}{2}}\\&=\Biggl.\pm\frac{1}{\sqrt{10}}\sqrt{x-4}\end{aligned}$}[/tex]
3. Tentukan ((fog)⁻¹)'
[tex]\large\text{$\begin{aligned}\left((f\circ g)^{-1}\right)'(x)&=\Biggl.\pm\frac{1}{\sqrt{10}}\left(\frac{1}{2\sqrt{x-4}}\cdot(x-4)'\right)\\&=\Biggl.\pm\frac{1}{2\sqrt{10}\sqrt{x-4}}\end{aligned}$}[/tex]
3. Tentukan ((fog)⁻¹)''
[tex]\large\text{$\begin{aligned}\left((f\circ g)^{-1}\right)''(x)&\Biggl.=\pm\frac{1}{2\sqrt{10}}\left (\frac{1}{2\sqrt{(x-4)^3}}\cdot(x-4)' \right )\\&=\Biggl.\pm\frac{1}{4\sqrt{10}\sqrt{(x-4)^3}}\end{aligned}$}[/tex]
4. Tentukan (((fog)⁻¹)'')⁻¹
[tex]\large\text{$\begin{aligned}&\Biggl.y=\mp\frac{1}{4\sqrt{10}\sqrt{(x-4)^3}}\\{\iff}&\Biggl.y\cdot4\sqrt{10}\sqrt{(x-4)^3}=\mp1\\{\iff}&\Biggl.\sqrt{(x-4)^3}=\mp\frac{1}{4\sqrt{10}\cdot y}\\.....\ &\sf kuadratkan,\ tanda\ \mp\ hilang\\{\iff}&\Biggl.(x-4)^3=\frac{1}{160y^2}\\{\iff}&\Biggl.x-4=\frac{1}{\sqrt[3]{160y^2}}=\frac{1}{\sqrt[3]{8\cdot20y^2}}\\{\iff}&\Biggl.x-4=\frac{1}{2\sqrt[3]{20}\sqrt[3]{y^2}}=\frac{1}{2\cdot20^{\frac{1}{3}}\cdot\sqrt[3]{y^2}}\end{aligned}$}[/tex]
[tex]\large\text{$\begin{aligned}{\iff}&\Biggl.x-4=\frac{1\cdot20^{\frac{2}{3}}}{2\cdot20^{\frac{1}{3}}\cdot\sqrt[3]{y^2}\cdot20^{\frac{2}{3}}}\\{\iff}&\Biggl.x-4=\frac{20^{\frac{2}{3}}}{2\cdot20\sqrt[3]{y^2}}=\frac{\sqrt[3]{400}}{2\cdot20\sqrt[3]{y^2}}\\{\iff}&\Biggl.x-4=\frac{\sqrt[3]{8\cdot50}}{2\cdot20\sqrt[3]{y^2}}=\frac{\cancel{2}\sqrt[3]{50}}{\cancel{2}\cdot20\sqrt[3]{y^2}}\\{\iff}&\Biggl.x-4=\frac{1}{20}\sqrt[3]{\frac{50}{y^2}}\\{\iff}&\Biggl.x=\frac{1}{20}\sqrt[3]{\frac{50}{y^2}}+4\end{aligned}$}[/tex]
Sehingga, bentuk akhirnya adalah:
[tex]\large\text{$\begin{aligned}\left(\left((f\circ g)^{-1}\right)''\right)^{-1}(x)=\frac{1}{20}\sqrt[3]{\frac{50}{x^2}}+4\end{aligned}$}[/tex]
5. Substitusikan x = √2
[tex]\large\text{$\begin{aligned}&\left(\left((f\circ g)^{-1}\right)''\right)^{-1}(\sqrt{2})\\&=\Biggl.\frac{1}{20}\sqrt[3]{\frac{50}{\left (\sqrt{2} \right )^2}}+4\\&=\Biggl.\frac{1}{20}\sqrt[3]{\frac{50}{2}}+4\\&=\Biggl.\bf\frac{1}{20}\sqrt[\bf3]{\bf25}+4\\&\therefore\ \sf terbukti!\end{aligned}$}[/tex]
19. (x-2)log(x^2+5x-50)=^(x-2)log (3x-2)tentukan himpunan penyelesaian diatas
Jawaban:
semoga membantu ,sorry kalau salah
20. jawablah soal linier brikut ini: 1. x+4y=30 2. -5x+y=5 3. 6x-y=2 4. 5x+y=50 5. x-5y=0
jawaban soal nya berupa titik titik pad sebuah garis
1) x + 4y = 30
x = 0 , y =7 1/2 --> A(0, 7 1/2)
y = 0 , x = 30 ---> B( 30,0)
buat garis AB (penyelesaianya)
2) -5x + y = 5
x = 0 . y = 5 --> C(0,5)
y =0 , x = -1 --> D(-1, 0)
buat garis CD
3) 6x - y = 2
x= 0 , y = -2 --> E(0,-2)
y = 0 ,x = 1/3 --> F ( 1/3 , 0)
buat garis EF
4) dan 5) .... sama cara nya dengan diatas
21. Q. [+50]Tentukan nilai x dari persamaan berikut.1) 5x – 11 = 2(x + 2)2) 2(x + 1) = 3(x – 1)
Penyelesaian:
1.)5x-11=2(x+2)
5x-11=2x+4
5x-2x=4+11
3x=15
x=5
----------------------------------------
2.)2(x+1)=3(x-1)
2x+2=3x-3
2+3=3x-2x
5=x
----------------------------------------
[tex] \boxed{ \colorbox{black}{ \sf{ \color{lightgreen}{ answered\:by\:Duone}}}} [/tex]
Penjelasan dengan langkah-langkah:
1. 5x – 11 = 2(x + 2)
5x - 11 = (2.x) + (2.2)
5x - 11 = 2x + 4
5x - 11 - 2x = 4
5x - 2x = 4 + 11
3x = 15
x = (15 ÷ 3)
x = 5
2. 2(x + 1) = 3(x – 1)
(2.x) + (2.1) = (3.x) - (3.1)
2x + 2 = 3x - 3
2x + 2 - 3x = -3
2x - 3x = -3 - 2
-x = -5
x = - (-5)
x = 5
22. Q. [+50]f(x) = 4x - x + 5xf(2) = ...
Penjelasan dengan langkah-langkah:
f(x) = 4x - x + 5x
f(2) = 4(2) - 2 + 5(2)
f(2) = (4 × 2) - 2 + (5 × 2)
f(2) = 8 - 2 + 10
f(2) = 6 + 10
f(2) = 16
Penjelasan dengan langkah-langkah:
f(x) = 4x - x + 5x
f(2) = 4(2) - 2 + 5(2)
f(2) = 8 - 2 + 10
f(2) = 6 + 10
f(2) = 16
23. 5x+20xy-3 dimana x=50,y=2
Jawaban:
5x+20xy-3 dimana x=50,y=2
maka :
5.50 + 20.50.2 - 3
= 250 + 2000 - 3
= 2250 - 3
= 2247
24. [+50]f(x) = 5x⁴ + 3x² - 2xf'(2) + f'(3) = __
Jawaban:
f(x) = 5x⁴ + 3x² - 2x
f'(x) = 4 . 5x^(4 - 1) + 2 . 3x^(2 - 1) - 2x^(1 - 1)
f'(x) = 20x³ + 6x - 2x⁰
f'(x) = 20x³ + 6x - 2(1)
f'(x) = 20x³ + 6x - 2
_________
f'(x) = 20x³ + 6x - 2
f'(2) = 20(2)³ + 6(2) - 2
f'(2) = 20(8) + 12 - 2
f'(2) = 160 + 12 - 2
f'(2) = 170
_________
f'(x) = 20x³ + 6x - 2
f'(3) = 20(3)³ + 6(3) - 2
f'(3) = 20(27) + 18 - 2
f'(3) = 540 + 18 - 2
f'(3) = 556
_________
f'(2) + f'(3)
=170 + 556
=726
Penjelasan dengan langkah-langkah:
f(x) = 5x⁴ + 3x² - 2x
f'(x) = 5.4x⁴-¹ + 3.2x²-¹ - 2.1x¹-¹
f'(x) = 20x³ + 6x¹ - 2x⁰
f'(x) = 20x³ + 6x - 2
f'(2) + f'(3)
= (20(2)³ + 6(2) - 2)) + (20(3)³ + 6(3) - 2))
= (20(8) + 12 - 2) + (20(27) + 18 - 2)
= (172 - 2) + (540 + 18 - 2)
= 170 + (558 - 2)
= 170 + 556
= 726
25. jawab baaang ^^ himpunan penyelesaian! Tentukan nilai x! 1. x + 3 = 6 2. 2x + 5x = 50 pliss :>
Tentukan nilai x!
1. x + 3 = 6
2. 2x + 5x = 50
x + 3 = 6
x = 6 - 3
nilai x = 3
2x + 5x = 50
7x = 50
nilai x = 50/7
26. 8 × 200-50 85:4+3,75 (10-31) 5x 2 X x 4 4+2) 5
Semoga dapat membantu
27. Qquuiizz (+50)1) Y²³ × Y⁴⁵ : Y⁶⁸ 2) f(x) = 5x - 4x + 8x - 5xf(7) = ...Sertakan cara!
[1] Hasil dari Y²³ × Y⁴⁵ : Y⁶⁸ adalah 1
[2] Nilai f(7) dari f(x) = 5x - 4x + 8x - 5x adalah 28
SOAL NO 1Diketahui:
Y²³ × Y⁴⁵ : Y⁶⁸Ditanyakan:
HasilJawab:
Sifat yg digunakan yaitu:
a^b × a^n = a^b + na^b : a^n = a^b - na⁰ = 1Y²³ × Y⁴⁵ : Y⁶⁸
=> Y^23 + 45 : Y^68
=> Y^68 : Y^68
=> Y^68 - 68
=> Y⁰
=> 1
SOAL NO 2Diketahui:
f(x) = 5x - 4x + 8x - 5xDitanyakan:
f(7)Jawab:
f(x) = 5x - 4x + 8x - 5x
f(7) = 5(7) - 4(7) + 8(7) - 5(7)
f(7) = 35 - 28 + 56 - 35
f(7) = -28 + 56
f(7) = 28
Atau...
f(x) = 5x - 4x + 8x - 5x
f(x) = x + 8x - 5x
f(x) = 9x - 5x
f(x) = 4x
f(7) = 4(7)
f(7) = 28
KESIMPULANHasil dari Y²³ × Y⁴⁵ : Y⁶⁸ adalah 1Nilai f(7) dari f(x) = 5x - 4x + 8x - 5x adalah 2828. tentukan nilai a, b, c[tex]x ^{2} + 5x = 50[/tex]
[tex] {x}^{2} + 5x = 50 \\ {x}^{2} + 5x - 50 = 0 \\ a = 1 | b = 5 | c = - 50[/tex]
Penjelasan dengan langkah-langkah:
Persamaan Kuadrat
Bentuk umum nya adalah ax² + bx + c = 0
[tex] {x}^{2} + 5x = 50 \\ {x}^{2} + 5x - 50 = 0[/tex]
Didapat;
a = 1 , b = 5 dan c = -50
29. Q. Himpunan•Tentukan nilai x!1. x + 3 = 62. 2x + 5x = 50
Jawaban:
1. x + 3 = 6
x = 6 - 3
x = 3
2. 2x + 5x = 50
7x = 50
x = 50 / 7
x = 7,1
Tentukan nilai x!
1. x + 3 = 6
2. 2x + 5x = 50
x + 3 = 6
x = 6 - 3
nilai x = 3
2x + 5x = 50
7x = 50
nilai x = 50/7
30. Kuis[+50]: [a] (9x-47 = 195-2x) _____________ (5x-2+x=9+3x+10)
Jawaban:
A) x = 22
B) x = 7
Penjelasan dengan langkah-langkah:
Persaman Linear
A) (9x - 47 = 195 - 2x)(9x + 2x = 195 + 47)
(11x = 242)
(x = 242 ÷ 11)
(x = 22)
jadi nilai x adalah 22
B) (5x - 2 + x = 9 + 3x + 10)(6x - 2 = 19 + 3x)
(6x - 3x = 19 + 2)
(3x = 21)
(x = 21 ÷ 3)
(x = 7)
jadi nilai x adalah 7
Detail
Mapel: Matematika
Materi: Persamaan Linear
#Semoga bermanfaat dan membantu
●▬▬๑۩۩๑▬▬●
░Prusmantex34░
●▬▬๑۩۩๑▬▬●
No 1
9x - 47 = 195 - 2x
9x + 2x = 195 + 47
11x = 242
x = 242/11
x = 22
No 25x - 2 + x = 9 + 3x + 10
5x + x - 3x = 9 + 10 + 2
6x - 3x = 19 + 2
3x = 21
x = 21/3
x = 7
• - • - • - • - • - • - • - • - • - • - • - • - • - • - • - •
ketika ruas akan di pindahkan maka..
positif (+) akan menjadi negatif (-)
negatif (-) akan menjadi positif (+)
contoh
- 7 + x = 8 - 3x
x + 3x = 8 + 7
31. Quiz(50+):Jika f(x) = 2x² + 5x dan g(x) = 1/x maka (f o g)(2) adalah …
diketahui :
f(x) = 2x² + 5x
g(x) = 1/x
ditanya :
(fog) (2)
jawab :
(fog) (x) = f(x) o f(g)
(fog) (x) = (2x² + 5x) o (1/x)
(fog) (x) = 2(1/x)² + 5(1/x)
(fog) (2) = 2(1/2)²+5(1/2)
(fog) (2) = 2(1/4) + 5/2
(fog) (2) = 1/2+5/2
(fog) (2) = 6/2 = 3
Jawaban:
Fungsi Komposisi dan InversPenjelasan dengan langkah-langkah:
f(x)=2x²+5x
g(x)=1/x
(fog)(x)=f(g(x))
=f(1/x)
=2(1/x)²+5(1/x)
=2(1/x²)+(5/x)
=(2/x²+5/x)
=(2/x²+5x/x²)
=(2+5x)/(x²)
(fog)(2)=(2+5(2)/(2²)
=(2+10)/(4)
=(12)/(4)
=3
Demikian
Semoga membantu dan bermanfaat!
32. [+50](9/10) f(x) = x² + 5x - 3x + 2, hitung bayangan untuk x = 1
Jawaban:
f(x) = x² + 5x - 3x + 2
f(1) = 1² + 5(1) - 3(1) + 2
f(1) = (1 × 1) + (5 × 1) - (3 × 1) + 2
f(1) = 1 + 5 - 3 + 2
f(1) = 6 - 3 + 2
f(1) = 3 + 2
f(1) = 5
Jawaban:
5
Penjelasan dengan langkah-langkah:
f(x) = x² + 5x - 3x + 2
f(1) = 1² + 5(1) - 3(1) + 2
= 1 + 5 - 3 + 2
= 6 - 3 + 2
= 3 + 2
= 5
33. [+50]1.) turunan pertama f(x) = 5x⁵ + 3x³ - 2x2.) x² - 10x + 16 = 0 (Rumus ABC)
1.) turunan pertama f(x) = 5x⁵ + 3x³ - 2x
[tex] \sf \: f(x) = 5 {x}^{5} + 3{x}^{3} - 2x[/tex]
[tex] \sf \: f'(x) = 5.5{x}^{5 - 1} + 3.3 {x}^{ 3 - 1} - 2 {x}^{1 - 1} [/tex]
[tex] \sf \: f'(x) = 25 {x}^{4} + 9 {x}^{2} - 2[/tex]
2.) x² - 10x + 16 = 0 (Rumus ABC)
[tex] \sf \:x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
[tex] \sf \: x = \frac{ - ( - 10)± \sqrt{( - 10) {}^{2} - 4.1.16 } }{2.1} [/tex]
[tex] \sf x = \frac{10± \sqrt{100 - 4.1.16} }{2} [/tex]
[tex] \sf \: x = \frac{10± \sqrt{100 - 64} }{2} [/tex]
[tex] \sf \: x = \frac{10± \sqrt{36} }{2} [/tex]
[tex]\sf \: x = \frac{10± \sqrt{ {6}^{2} } }{2} [/tex]
[tex]\sf \: x = \frac{10± 6 }{2} [/tex]
[tex] \sf x_1 = \frac{10 + 6}{2} = \frac{16}{2} = 8[/tex]
[tex] \sf x_2 = \frac{10 - 6}{2} = \frac{4}{2} = 2[/tex]
#Koreksi
1.) turunan pertama f(x) = 5x⁵ + 3x³ - 2x
penyelesaian :
f(x) = 5x⁵ + 3x³ - 2x
f'(x) = 5.5.x^5-1 + 3.3.x^3-1 - 1.2.x^1-1
f'(x) = 25x⁴ + 9x² - 2x⁰
f'(x) = 25x⁴ + 9x² - 2
2.) x² - 10x + 16 = 0 (Rumus ABC)
x = - (-10) ± √(-10)²- 4 × 1 × 16 / 2×1
x = 10 ± √(-10)²- 4 × 1 × 16 / 2×1
x = 10 ± √10²- 4 × 1 × 16 / 2×1
x = 10 ± √36 / 2×1
x = 10 ± 6 / 2×1
x = 10 ± 6 / 2
x1 = 10 + 6 / 2
= 16/2
= 8
x2 = 10 - 6 / 2
= 4/2
= 2
[tex]x =8 \\ x= 2[/tex]
#semangatbelajar
34. Quiz easy [+50]________________________________f(x) = 5x + 7 - 3f(1/2) = ?________________________________100 Following -,-
Jawaban:
penjelasan:
f(x) = 5x + 7 - 3
f(½) = 5(½) + 7 - 3
f(½) = 5/2 + 7 - 3
f(½) = 5/2 + 4
f(½) = 13/2
[tex]f \rm(x) = 5x + 7 - 3[/tex]
[tex]f \rm( \frac{1}{2} ) = 5( \dfrac{1}{2} ) + 7 - 3[/tex]
[tex]f \rm( \frac{1}{2} ) = (5 \times \dfrac{1}{2} ) + 7 - 3[/tex]
[tex]f \rm( \frac{1}{2} ) = \dfrac{5}{2} + 7- 3[/tex]
[tex]f \rm( \frac{1}{2} ) = \dfrac{5}{2} + 4[/tex]
[tex]f \rm( \frac{1}{2} ) = \dfrac{5}{2} + \dfrac{4}{1} [/tex]
[tex]f \rm( \frac{1}{2} ) = \dfrac{5}{2} + \dfrac{8}{2} [/tex]
[tex]f \rm( \frac{1}{2} ) = \red{ \bold{ \dfrac{13}{2} }} \: Atau \: \red{ \bold{ 6 \dfrac{1}{2} }}[/tex]
35. [+50] 1.) 3x = 60/x⁰ + x⁰ x = __ 2.) 2x - 4 = 5x + 20 x = __
Penyelesaian soal :
[tex] \sf 3x = \frac{60}{ {x}^{0 } } + {x}^{0} [/tex]
[tex] \sf 3x = \frac{60}{1} + {x}^{0} [/tex]
[tex] \sf 3x = \frac{60}{1} + 1[/tex]
[tex] \sf 3x = 60 + 1[/tex]
[tex] \sf 3x = 61[/tex]
[tex] \sf x = \frac{61}{3} [/tex]
.[tex] \sf 2x - 4= 5x + 20[/tex]
[tex] \sf 2x - 4 - 5x = 20[/tex]
[tex] \sf 2x - 5x = 20 + 4[/tex]
[tex] \sf - 3x = 20 + 4[/tex]
[tex] \sf - 3x = 24[/tex]
[tex] \sf x = - 8[/tex]
____Jess
3x = 60/x⁰ + x⁰
3x = 60 ÷ x⁰ + x⁰
3x = 60 + 1
3x = 61
x = 61/3
[tex]x = 20 \frac{1}{3} [/tex]
__________________________2x - 4 = 5x + 20
2x - 5x = 20 + 4
-3x = 24
x = 24 ÷ ( - 3 )
[tex]x = -8 [/tex]
[tex]\purple{\boxed{\blue{\boxed{\red{\tt{\ \: \pink{{⇢ - By : » \: XxDarknessxX࿐ }}}}}}}}[/tex]
36. [+50](4/10)1.) 5x + 5 = 202.) 30x + 5 = 85solve x ≈
Jawaban:
5x + 5 = 20
5x = 20 - 5
5x = 15
x = 15/5
x = 3
30x + 5 = 85
30x = 85 - 5
30x = 80
x = 80/30
x = (80 ÷ 10)/(30 ÷ 10)
x = 8/3
5x + 5 = 20
5x = 15
x = 15 ÷ 5
x = 3
[tex]\sf ↓ ↓ ↓↓[/tex]
30x + 5 = 85
30x = 80
x = 80/30
x = 8/3
[tex] \mathscr \red{→} \: \pink{Riiax} \: \purple{←}[/tex]
37. [+50]1.) 2x + 3 = 5x - 122.) 5x + 10 = 200maka x,
Jawaban:
1.) 2x + 3 = 5x - 12
Nilai x = ...
2x + 3 = 5x - 12
2x - 5x = - 12 - 3
-3x = -15
x = -15/-3
x = 5
2.) 5x + 10 = 200
5x = 200 - 10
5x = 190
x = 190/5
x = 38
Penjelasan dengan langkah-langkah:
1.) 2x + 3 = 5x - 12
2x - 5x = -12 - 3
-3x = -15
x = 15/3
x = 5
2.) 5x + 10 = 200
5x = 200 - 10
5x = 190
x = 190 ÷ 5
x = 38
38. Tentukan faktor dari persamaan : [tex]\x^2 + 5x - 50[/tex]
[tex]\ x^2 + 5x - 50[/tex]
[tex]\ (x + 10)(x - 5)[/tex]
39. Hm 39/50 ;-;5x + 4x × 5y - 4yx = 2y = 4
[tex]5x + 4x × 5y - 4y[/tex]
[tex]5(2) + 4(2) × 5(4) - 4(4) [/tex]
[tex]10 + 8 × 20 - 16[/tex]
[tex]10 + 160 - 16[/tex]
[tex]170 - 16[/tex]
[tex]\red{\boxed{154}}[/tex]
[tex]\blue{\boxed{\blue{\boxed{\purple{\tt{\ \: \red{{ ༻ 彡 ꒐꓄ꁴ \: ꒻꒤ꇙ꓄ \: ꂵꏂ彡 ༺ }}}}}}}}[/tex]
Penyelesaian :Dik :
• x = 2
• y = 4
Dit :
• 5x + 4x × 5y - 4y
Jawab :
• 5x + 4x × 5y - 4y
• 5(2) + 4(2) × 5(4) - 4(4)
• = ( 5 + 5 ) + 4(2) × 5(4) - 4(4)
• = 10 + 4(2) × 5(4) - 4(4)
• = 10 + ( 4 + 4 ) × 5(4) - 4(4)
• = 10 + 8 × 5(4) - 4(4)
• = 10 + 8 × ( 5 + 5 + 5 + 5 ) - 4(4)
• = 10 + 8 × ( 10 + 5 + 5 ) - 4(4)
• = 10 + 8 × ( 10 + 10 ) - 4(4)
• = 10 + 8 × 20 - 4(4)
• = 10 + 8 × 20 - ( 4 + 4 + 4 + 4 )
• = 10 + 8 × 20 - ( 8 + 4 + 4 )
• = 10 + 8 × 20 - ( 8 + 8 )
• = 10 + 8 × 20 - 16
• = 10 + ( 8 × 20 ) - 16
• = 10 + 160 - 16
• = ( 10 + 160 ) - 16
• = 170 - 16
• = 154
#Cara kebawah terlampir
40. Q. [÷50] 1. Terlampir2. f(x) = 6x² + 76x² - 5x² f"(x) =
Penjelasan dengan langkah-langkah:
1. TABEL DISTRIBUSI FREKUENSI
No. NAMA BUAH JUMLAH BIBIT
1. APEL 18
2. JAMBU 36
3. JERUK 24
4. MANGGA 30
5. MELON 12
→ → J U M L A H 120
2.
f(x) = 6x² + 76x² - 5x²
f'(x) = 12x + 152x – 10x
f"(x) = 164 – 10
f"(x) = 154terlampirsemoga membantu ☺️